The heights of John, Joey, and Peter are measured to be 1.68 m, 1.63 m, and 1.64 m respectively, each correct to 1 cm. Find the upper limit of the average height of John, Joey, and Peter.
Solution
Hints:
1.655 m
Each measurement is to the nearest 0.01 m, so error is \\pm 0.005 \\text{ m}. Upper limits: 1.68 + 0.005 = 1.685 \\text{ m}, 1.63 + 0.005 = 1.635 \\text{ m}, 1.64 + 0.005 = 1.645 \\text{ m}. Average = \\frac{1.685 + 1.635 + 1.645}{3} = \\frac{4.965}{3} = 1.655 \\text{ m}.