The heights of John, Joey, and Peter are measured to be 1.68 m, 1.63 m, and 1.64 m respectively, each correct to 1 cm. Find the lower limit of the average height of John, Joey, and Peter.
Solution
Hints:
1.635 m
Each measurement is to the nearest 0.01 m, so error is \\pm 0.005 \\text{ m}. Lower limits: 1.68 - 0.005 = 1.675 \\text{ m}, 1.63 - 0.005 = 1.625 \\text{ m}, 1.64 - 0.005 = 1.635 \\text{ m}. Average = \\frac{1.675 + 1.625 + 1.635}{3} = \\frac{4.935}{3} = 1.635 \\text{ m}.